x^2-26x-1680=0

Solution for x^2-26x-1680=0 equation:

x^2-26x-1680=0

a = 1; b = -26; c = -1680;
Δ = b2-4ac
Δ = -262-4·1·(-1680)
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-86}{2*1}=\frac{-60}{2}
=-30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+86}{2*1}=\frac{112}{2}
=56
$